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properties</a></label></li><li class=""><label style="padding-left: 14px"><i class="fa fa-fw"></i><a href="../440/particle-interactions.html">Particle interactions</a></label></li><li class=""><label style="padding-left: 14px"><i class="fa fa-fw"></i><a href="../441/quarks.html">Quarks</a></label></li><li class=""><label style="padding-left: 14px"><i class="fa fa-fw"></i><a href="../442/the-standard-model.html">The Standard Model</a></label></li></ul></li><li class="expanded parent"><label style="padding-left: 0px"><a class="expander" href="#" style="font-size: .9em"><i class="fa fa-fw fa-caret-right"></i></a><a href="../1132/ahl-quantum.html">AHL Quantum</a></label><ul class="side-nav level-1"><li class=""><label style="padding-left: 14px"><i class="fa fa-fw"></i><a href="../1135/photoelectric-effect-and-photons.html">Photoelectric effect and photons</a></label></li><li class="expanded parent selected"><label style="padding-left: 14px"><i class="fa fa-fw"></i><a href="wave-particle-duality.html">Wave particle duality</a></label></li><li class=""><label style="padding-left: 14px"><i class="fa fa-fw"></i><a href="../1133/atomic-models.html">Atomic models</a></label></li></ul></li></ul></div> <div class="hidden-xs hidden-sm"> <button class="btn btn-default btn-block text-xs-center" data-toggle="modal" data-target="#modal-feedback" style="margin-bottom: 10px"><i class="fa fa-send"></i>&nbsp;&nbsp;Feedback</button> </div> </div> <div class="col-md-9" id="main-column"> <h1 class="page_title"> Wave particle duality <a href="#" class="mark-page-favorite pull-right" data-pid="1134" title="Mark as favorite" onclick="return false;"><i class="fa fa-star-o"></i></a> </h1> <ol class="breadcrumb"> <li><a href="../../../physics.html"><i class="fa fa-home"></i></a><i class="fa fa-fw fa-chevron-right divider"></i></li><li><a href="../354/atomic-nuclear-and-particles.html">Atomic, nuclear and particles</a><i class="fa fa-fw fa-chevron-right divider"></i></li><li><a href="../1132/ahl-quantum.html">AHL Quantum</a><i class="fa fa-fw fa-chevron-right divider"></i></li><li><span class="gray">Wave particle duality</span></li> <span class="pull-right" style="color: #555" title="Suggested study time: 20 minutes"><i class="fa fa-clock-o"></i> 20&apos;</span> </ol> <article id="main-article"> <p><img alt="" src="../../quantum/quantum.jpg" style="float: left; width: 250px; height: 133px;">The evidence from the photoelectric effect, Compton scattering and pair production that electromagnetic radiation can have quantum properties indicates that matter may have wave properties. Here we will consider this possibility.</p> <hr class="hidden-separator"> <div class="panel panel-turquoise panel-has-colored-body"> <div class="panel-heading"> <div> <p>Key Concepts</p> </div> </div> <div class="panel-body"> <div> <div class="panel panel-has-colored-body panel-has-border panel-turquoise"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Electron diffraction</p> </div> </div> <div class="panel-body"> <div> <p>When electrons are passed through a thin lattice and onto a phosphorescence screen, rings of differing intensities&nbsp;are produced. This phenomenon can only be explained by the diffraction and interference of the electrons and, just as we do for light, we can calculate an equivalent wavelength for the electrons.</p> <div class="video-embed vimeo"><iframe allow="accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture" allowfullscreen="" mozallowfullscreen="" webkitallowfullscreen="" height="420" width="100%" src="https://player.vimeo.com/video/376909702"></iframe></div> <p>A simplified approach is to consider what would happen if electrons passed through double slits.</p> <div class="video-embed vimeo"><iframe allow="accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture" allowfullscreen="" mozallowfullscreen="" webkitallowfullscreen="" height="420" width="100%" src="https://player.vimeo.com/video/376909805"></iframe></div> </div> </div> <div class="panel-footer"> <div>&nbsp;</div> </div> </div> <div class="panel panel-has-colored-body panel-has-border panel-turquoise panel-expandable"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>De Broglie wavelength</p> </div> </div> <div class="panel-body"> <div> <p>Electrons can be thought of, not as small spheres, but as a wave function that gives probability distribution of finding the particle in a region of space. The de Broglie wavelength of matter can be calculated as follows:</p> <p style="text-align: center;"><span class="math-tex">\(\lambda={h\over p}\)</span></p> <ul> <li><span class="math-tex">\(\lambda\)</span>&nbsp;is the de Broglie wavelength (m)</li> <li><span class="math-tex">\(h\)</span>&nbsp;is Planck&#39;s constant (Js)</li> <li><span class="math-tex">\(p\)</span>&nbsp;is the momentum of the particle (<span class="math-tex">\(=mv\)</span>&nbsp;in kgms<sup>-1</sup>)</li> </ul> <p>This equation helps to explain why large particles do not&nbsp;exhibit wave properties. A human walking through a door, for example, has a de Broglie wavelength in the order&nbsp;<span class="math-tex">\({10^{-33}\over 10^2}=10^{-35}\)</span>&nbsp;m, far smaller than the gap.&nbsp;</p> <p>On the other hand, as an electron approaches a slit, the preceding wave function maps out the probable positions and it is diffracted. The combination of many electrons will forge the maxima in the diffraction pattern.</p> <div class="video-embed vimeo"><iframe allow="accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture" allowfullscreen="" mozallowfullscreen="" webkitallowfullscreen="" height="420" width="100%" src="https://player.vimeo.com/video/376909729"></iframe></div> </div> </div> <div class="panel-footer"> <div>&nbsp;</div> </div> </div> </div> </div> <div class="panel-footer"> <div>&nbsp;</div> </div> </div> <div class="panel panel-has-colored-body panel-yellow"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Essentials</p> </div> </div> <div class="panel-body"> <div> <div class="panel panel-has-colored-body panel-has-border panel-yellow"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Schr&ouml;dingers model</p> </div> </div> <div class="panel-body"> <div> <p>The probability of an electron being in a particular position at a particular time&nbsp;is defined by Schr&ouml;dinger as the square of the amplitude of the wave function, where the wave function varies with position and time. The wave function is&nbsp;denoted as&nbsp;<span class="math-tex">\(\Psi\)</span>.</p> <p>The probability of an electron being at a given radius within a given volume&nbsp;is given by:</p> <p style="text-align: center;"><span class="math-tex">\(P(r)=|\Psi|^2\Delta V\)</span></p> <ul> <li><span class="math-tex">\(P(r)\)</span>&nbsp;is the probability of the electron at a given radius</li> <li><span class="math-tex">\(|\Psi|\)</span>&nbsp;is the magnitude of the wave equation</li> <li><span class="math-tex">\(\Delta V\)</span>&nbsp;is the&nbsp;volume</li> </ul> <div class="video-embed vimeo"><iframe allow="accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture" allowfullscreen="" mozallowfullscreen="" webkitallowfullscreen="" height="420" width="100%" src="https://player.vimeo.com/video/376910008"></iframe></div> </div> </div> <div class="panel-footer"> <div>&nbsp;</div> </div> </div> <div class="panel panel-has-colored-body panel-has-border panel-yellow panel-expandable"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Heisenberg&#39;s uncertainty principle</p> </div> </div> <div class="panel-body"> <div> <p>To identify the onward path of a particle, we must know its position and momentum. We have two options to make such observations for electrons, both of which involve passing electrons through a narrow opening:</p> <ul> <li>To allow all electrons in a parallel beam to pass comfortably through a wide slit. We can be sure of the onward direction and momentum, but the range of positions is large and uncertain.</li> <li>To constrain the beam of electrons to within a narrow slit. For the electrons that happen to pass through the slit, we can be sure of their position, but the consequential diffraction effect makes certainty of the path (and, hence, momentum) impossible.</li> </ul> <p>The Heisenberg uncertainty principle describes the inherent impossibility of measuring both momentum and position with certainty&nbsp;as an equation:</p> <p style="text-align: center;"><span class="math-tex">\(\Delta p \Delta x \geq{h\over 4\pi}\)</span></p> <ul> <li><span class="math-tex">\(\Delta p\)</span>&nbsp;is&nbsp;uncertainty in momentum (kgms<sup>-1</sup>)</li> <li><span class="math-tex">\(\Delta x\)</span>&nbsp;is&nbsp;uncertainty in position (m)</li> <li><span class="math-tex">\(h\)</span>&nbsp;is Planck&#39;s constant (Js)</li> </ul> <p>A similar relationship can be stated for energy and time:</p> <p style="text-align: center;"><span class="math-tex">\(\Delta E\Delta t\geq{h\over 4\pi}\)</span></p> <ul> <li><span class="math-tex">\(\Delta E\)</span>&nbsp;is uncertainty in energy (J)</li> <li><span class="math-tex">\(\Delta t\)</span>&nbsp;is uncertainty in time (s)</li> </ul> <div class="video-embed vimeo"><iframe allow="accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture" allowfullscreen="" mozallowfullscreen="" webkitallowfullscreen="" height="420" width="100%" src="https://player.vimeo.com/video/376909828"></iframe></div> <p>We can use the uncertainty principle to estimate&nbsp;the energy of the ground state of an atom,&nbsp;the impossibility of an electron existing within a nucleus, and the lifetime of an electron in an excited energy state. In each case we need to assume that an uncertainty is a similar size to a quantity.</p> <h4>Ground state</h4> <p>The ground state of a hydrogen&nbsp;atom sees the electron in the lowest energy level (<span class="math-tex">\(n=1\)</span>). Substituting the radius of the first energy level (<span class="math-tex">\(0.529 \text{ }Å=0.529\times 10^{-10} \text{ m}\)</span>) as&nbsp;<span class="math-tex">\(\Delta x\)</span>, we can find&nbsp;<span class="math-tex">\(\Delta p\)</span>:</p> <p style="text-align: center;"><span class="math-tex">\(\Delta p \Delta x \geq{h\over 4\pi}\)</span></p> <p style="text-align: center;"><span class="math-tex">\(\Delta p\geq{6.63\times10^{-34}\over 4\pi 0.529\times10^{-10}}\)</span></p> <p style="text-align: center;"><span class="math-tex">\(\Delta p\geq10^{-24}\text{ kg ms}^{-1}\)</span></p> <p>Since the ground state has no angular momentum, all momentum is linear. Therefore, we can convert this into kinetic energy:</p> <p style="text-align: center;"><span class="math-tex">\(E_k={1\over 2}mv^2={1\over 2}{p^2\over m}\)</span></p> <p style="text-align: center;"><span class="math-tex">\(E_k={1\over 2}{(10^{-24})^2\over 9.11\times 10^{-31}}\approx5\times 10^{-19}\text{ J}\approx3\text{ eV}\)</span></p> <p>Note that the electron also has potential energy, but this order of magnitude is accurate.</p> <h4>Electron in the nucleus</h4> <p>To consider the probability of an electron existing in the nucleus, we need to substitute the radius of the nucleus&nbsp;as <span class="math-tex">\(\Delta x\)</span>&nbsp;to find <span class="math-tex">\(\Delta p\)</span>. In the case of hydrogren, the nucleon number is 1 (<a href="../1152/ahl-nuclear-radius.html" title="AHL Nuclear radius">Nuclear radius</a>) , so&nbsp;<span class="math-tex">\(R_0\)</span>&nbsp;is substituted:</p> <p style="text-align: center;"><span class="math-tex">\(\Delta p \Delta x \geq{h\over 4\pi}\)</span></p> <p style="text-align: center;"><span class="math-tex">\(\Delta p\geq{6.63\times10^{-34}\over 4\pi 1.2\times10^{-15}}\)</span></p> <p style="text-align: center;"><span class="math-tex">\(\Delta p\geq4.4\times 10^{-20}\text{ kg ms}^{-1}\)</span></p> <p>Now estimating the consequential velocity of the electron reveals the impossibility of this position:</p> <p style="text-align: center;"><span class="math-tex">\(v={p\over m}\)</span></p> <p style="text-align: center;"><span class="math-tex">\(v={4.4\times 10^{-20}\over 9.11\times 10^{-31}}\approx 5\times 10^{10}\text{ ms}^{-1}\)</span></p> <p>The order of magnitude of the velocity is larger than the speed of light.</p> <p>An atom will not collapse for the same reason; the electron would be confined into too small a space.</p> <h4>Excited energy states</h4> <p>To find the lifetime of an electron in a particular energy state, we use the second of the above Heisenberg uncertainty principle inequalities. For example, let us consider the ground state:</p> <p style="text-align: center;"><span class="math-tex">\(\Delta E\Delta t\geq{h\over 4\pi}\)</span></p> <p style="text-align: center;"><span class="math-tex">\(\Delta t\geq{6.63\times 10^{-34}\over 4\pi(13.6\times 1.6\times 10^{-19})}\)</span></p> <p style="text-align: center;"><span class="math-tex">\(\Delta t\geq2.4\times 10^{-17}\text{ s}\)</span></p> <p>As the energy state increases, the likely time decreases. An electron could remain in the ground state forever, but this calculation provides an illustration of how you might estimate the times for other energy states.</p> <div class="video-embed vimeo"><iframe allow="accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture" allowfullscreen="" mozallowfullscreen="" webkitallowfullscreen="" height="420" width="100%" src="https://player.vimeo.com/video/388879909"></iframe></div> </div> </div> <div class="panel-footer"> <div>&nbsp;</div> </div> </div> </div> </div> </div> <div class="panel panel-has-colored-body panel-green"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Test Yourself</p> </div> </div> <div class="panel-body"> <div> <p><em>Use quizzes&nbsp;to practise application of theory.</em></p> <br><a class="btn btn-primary btn-block text-center" data-toggle="modal" href="#15e6fff2"><i class="fa fa-play"></i> START QUIZ!</a><div class="modal fade modal-slide-quiz" id="15e6fff2"> <div class="modal-dialog" style="width: 95vw; max-width: 960px"> <div class="modal-content"> <div class="modal-header slide-quiz-title"> <h4 class="modal-title" style="width: 100%;"> Wave nature of matter <strong class="q-number pull-right"> <span class="counter">1</span>/<span class="total">1</span> </strong> </h4> </div> <div class="modal-body p-xs-3"> <div class="slide-quiz" data-stats="6-359-1134" style="opacity: 0"> <div class="exercise shadow-bottom"><div class="q-question"><p>The diagram represents the electron gun in an electron diffraction experiment.</p><p style="text-align: center;"><img alt="" height="216" src="../../screenshot-2019-10-19-at-08.37.54.png" width="241"></p><p>The ratio <span class="math-tex">\(V_2\over V_1\)</span> is approximately:</p></div><div class="q-answer"><p><label class="radio"> <input class="c" type="radio"> <span>1000</span></label> </p><p><label class="radio"> <input type="radio"> <span>0.1</span></label> </p><p><label class="radio"> <input type="radio"> <span>10</span></label> </p><p><label class="radio"> <input type="radio"> <span>0.001</span></label> </p></div><div class="q-explanation"><p><span class="math-tex">\(V_1\)</span> causes current to flow in the filament resulting in an increase in temperature. This requires about 5 V.</p><p><span class="math-tex">\(V_2\)</span> is the potential difference for acceleration, which is in the order of kV.</p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>The diagram represents the electron gun in an electron diffraction experiment.</p><p style="text-align: center;"><img alt="" height="216" src="../../screenshot-2019-10-19-at-08.37.54.png" width="241"></p><p>If <span class="math-tex">\(V_1 = 10\text{ V}\)</span> and <span class="math-tex">\(V_2 = 1\text{ kV}\)</span>, the kinetic energy of electrons will be:</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>10 eV</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>1 keV</span></label> </p><p><label class="radio"> <input type="radio"> <span>10 keV</span></label> </p><p><label class="radio"> <input type="radio"> <span>110 eV</span></label> </p></div><div class="q-explanation"><p>Kinetic energy in eV is numerically the same as the accelerating potential difference in V.</p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>The spacing of atoms in a thin film of graphite is approximately:</p></div><div class="q-answer"><p><label class="radio"> <input class="c" type="radio"> <span>0.1 nm</span></label> </p><p><label class="radio"> <input type="radio"> <span>0.1 mm</span></label> </p><p><label class="radio"> <input type="radio"> <span>0.1 pm</span></label> </p><p><label class="radio"> <input type="radio"> <span>0.1 μm</span></label> </p></div><div class="q-explanation"><p>The order of magnitude of atomic spacing is 10<sup>-10</sup> m, 1 Å</p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>The de Broglie wavelength of electrons with 1 keV kinetic energy is approximately the same as the wavelength of:</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>Microwaves</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>X-rays</span></label> </p><p><label class="radio"> <input type="radio"> <span>Visible light</span></label> </p><p><label class="radio"> <input type="radio"> <span>UV light</span></label> </p></div><div class="q-explanation"><p>Both are in the region of 10<sup>-10</sup> m</p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>What is the momentum of electrons with de Broglie wavelength 10<sup>-10</sup> m?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>6.6 x 10<sup>-34</sup> Ns</span></label> </p><p><label class="radio"> <input type="radio"> <span>1.6 x 10<sup>-29</sup> Ns</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>6.6 x 10<sup>-24</sup> Ns</span></label> </p><p><label class="radio"> <input type="radio"> <span>1.6 x 10<sup>-9</sup> Ns</span></label> </p></div><div class="q-explanation"><p><span class="math-tex">\(p = {h\over λ}\)</span>​​​​​​​</p><p><span class="math-tex">\(h = 6.6 \times 10^{-34}\text{ Js}\)</span></p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>Which of the following statements is the most correct?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>Electrons are packets of waves.</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>Electrons are particles.</span></label> </p><p><label class="radio"> <input type="radio"> <span>Electrons are sometimes waves, sometimes particles.</span></label> </p><p><label class="radio"> <input type="radio"> <span>Electrons are waves and particles.</span></label> </p></div><div class="q-explanation"><p>Electrons are particles whose position is given by a wave equation. This one is certainly a good discussion starter; it's a nature of science question.</p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>A particle of mass <span class="math-tex">\(m\)</span> and charge <span class="math-tex">\(q\)</span> is accelerated through a potential difference <span class="math-tex">\(V\)</span>.</p><p>The momentum of the particle is:</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span><span class="math-tex">\(\sqrt{mVq\over 2}\)</span></span></label></p><p><label class="radio"> <input class="c" type="radio"> <span><span class="math-tex">\(\sqrt{2mVq}\)</span></span></label></p><p><label class="radio"> <input type="radio"> <span><span class="math-tex">\(\sqrt{2Vq\over m}\)</span></span></label></p><p><label class="radio"> <input type="radio"> <span><span class="math-tex">\(\sqrt{2V\over qm}\)</span></span></label></p></div><div class="q-explanation"><p><span class="math-tex">\(Vq = {1\over2}mv^2={1\over 2}{p^2\over m}\)</span></p><p><span class="math-tex">\(p=\sqrt{2mVq} \)</span></p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>An electron is put into a cubic box of side 10<sup>-10</sup> m.</p><p>The minimum uncertainty in its momentum is in the order of:</p></div><div class="q-answer"><p><label class="radio"> <input class="c" type="radio"> <span>10<sup>-25</sup> Ns</span></label> </p><p><label class="radio"> <input type="radio"> <span>10<sup>-10</sup> Ns</span></label> </p><p><label class="radio"> <input type="radio"> <span>10<sup>-20</sup> Ns</span></label> </p><p><label class="radio"> <input type="radio"> <span>10<sup>-34</sup> Ns</span></label> </p></div><div class="q-explanation"><p><span class="math-tex">\(ΔxΔp = {h\over 4π} ≈ 10^{-35}\)</span></p><p>We know electron is in the box but not exactly where within, so <span class="math-tex">\(Δx = 10^{-10}\text{  m}\)</span>​​​​​​​<sup> </sup></p><p><span class="math-tex">\(\Delta p=10^{-35}\div 10^{-10}\)</span>​​​​​​​</p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>The image represents a wave packet that defines the position of an electron.</p><p style="text-align: center;"><img alt="" src="../../wavepart4.png" style="width: 537px; height: 130px;"></p><p>The electron is most likely to be in position:</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>A</span></label> </p><p><label class="radio"> <input type="radio"> <span>B</span></label> </p><p><label class="radio"> <input type="radio"> <span>D</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>C</span></label> </p></div><div class="q-explanation"><p>The probability is given by amplitude<sup>2</sup>.</p><p>The amplitude is greatest in the middle even though the displacent at this time is zero.</p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="exercise shadow-bottom"><div class="q-question"><p>A shot gun fires thousands of small balls. When they leave the end of the gun the balls:</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>continue in a straight line.</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>spread out due to the expansion of the surrounding gas.</span></label> </p><p><label class="radio"> <input type="radio"> <span>spread out due to diffraction.</span></label> </p><p><label class="radio"> <input type="radio"> <span>all have the same velocity.</span></label> </p></div><div class="q-explanation"><p>Small balls do not exhibit quantum effects.</p></div><div class="slide-q-actions"><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div> </div> </div> <div class="modal-footer slide-quiz-actions"> <div class=""> <div class="pull-left pull-xs-none mb-xs-3"> <button class="btn btn-default d-xs-none btn-prev"> <i class="fa fa-arrow-left"></i>&nbsp;&nbsp;Prev </button> 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