File "CE, Topic 1.1.5 - Ref from PaperPlainz on Vimeo.vtt"
Path: /PaperPlainz/Topic 1 Concept Explanations/CE, Topic 115 - Ref from PaperPlainz on Vimeovtt
File size: 7.53 KB
MIME-type: text/plain
Charset: utf-8
WEBVTT
00:00.000 --> 00:07.000
The topic of this video is estimation, we will discuss how to use estimation when measuring
00:07.000 --> 00:12.360
something and when working with graphs and we'll talk about how to round when carrying
00:12.360 --> 00:14.720
out calculations.
00:14.720 --> 00:19.760
When you measure something and read your measuring instrument, you never actually get an exact
00:19.760 --> 00:20.760
value.
00:20.760 --> 00:25.800
Let's say we are measuring the length of this line using a ruler.
00:25.800 --> 00:30.680
When writing down the measured value, we will need to use estimation.
00:30.680 --> 00:37.520
Looking at the ruler, I would say that the length of this line is approximately 5.3 cm,
00:37.520 --> 00:40.280
assuming that the ruler is in centimeters.
00:40.280 --> 00:45.080
Of course your estimation might be slightly different, which is what often happens when
00:45.080 --> 00:47.680
we estimate something.
00:47.680 --> 00:52.080
In some cases, you might have to make an estimation based on a graph.
00:52.080 --> 00:56.080
This graph shows how the speed of an object varies with time.
00:56.080 --> 01:00.480
The area under this graph is a distance traveled by this object.
01:00.480 --> 01:02.840
No worries if you haven't learned this yet.
01:02.840 --> 01:07.200
Here we are simply interested in estimating the area under the graph.
01:07.200 --> 01:10.480
We can do this by working with the small squares.
01:10.480 --> 01:19.480
We have approximately 42 full squares and about 9 squares that we will count as half squares.
01:19.480 --> 01:25.520
Of course, some of these half squares are more and some less than half of a square.
01:25.520 --> 01:32.040
But overall, these differences approximately balance each around and give us an area of 4.5
01:32.040 --> 01:37.400
squares, which adds up to a total of 46.5 squares.
01:37.400 --> 01:44.640
Since the horizontal side of each square represents 2 seconds and the vertical side represents
01:44.640 --> 01:46.760
1 meter per second.
01:46.760 --> 01:52.800
The area of 1 square is the product of these two, which gives us 2 meters.
01:52.800 --> 01:59.520
So since we have 46.5 squares and 1 square represents 2 meters, the distance traveled
01:59.520 --> 02:08.040
by this object during these 18 seconds is 2 times 46.5, which is 93 meters.
02:08.040 --> 02:12.720
Rounding is a type of estimation, so let's see how do we round after we carry out
02:12.720 --> 02:14.760
a calculation.
02:14.800 --> 02:17.000
Then we add or subtract.
02:17.000 --> 02:22.240
We need to round to the same decimal place as in the least accurate number.
02:22.240 --> 02:28.000
For multiplication and division, we round to the same number of significant figures as
02:28.000 --> 02:30.600
in the least accurate number.
02:30.600 --> 02:35.920
And when we raise a number to a power or take its root, we need to round to the same number
02:35.920 --> 02:40.080
of significant figures as in this original number.
02:40.080 --> 02:44.440
Let's try to understand these rules a bit better through some examples.
02:44.440 --> 02:51.760
This 1,700 plus 247 is equal to 2,947.
02:51.760 --> 02:59.800
The last significant figure in the 2,700 is here and in 247 it's here.
02:59.800 --> 03:06.040
This 7 is in the 100's place and this 7 is in the 1's place.
03:06.040 --> 03:12.240
Because of this, 2,700 is the least accurate number in the calculation.
03:12.240 --> 03:15.600
So we will round our result to the 100.
03:15.600 --> 03:18.840
This gives us 2,900.
03:18.840 --> 03:26.240
1.2278 minus 0.036 is 1.1918.
03:26.240 --> 03:32.240
In the first number, 8 is the last significant figure and in the second number, it is 6.
03:32.240 --> 03:38.600
8 is at the 10,000's place and 6 is at the 1000's place.
03:38.600 --> 03:42.120
So 0.036 is the least accurate.
03:42.120 --> 03:50.920
Therefore we will round to the 1000's place in our answer, which gives us 1.192.
03:50.920 --> 03:53.400
Let's see multiplication and division.
03:53.400 --> 04:00.080
21.0 times 0.05 gives us 1.05.
04:00.080 --> 04:08.080
21.0 has 3 significant figures since the 0 after the decimal place is a significant figure.
04:08.080 --> 04:13.520
And 0.05 has only 1 significant figure, which is the 5.
04:13.520 --> 04:17.720
The 0's before the 5 to not count as significant figures.
04:17.720 --> 04:23.280
Now we have to round to the least amount of significant figures that we see in our numbers.
04:23.280 --> 04:27.000
This is 1 significant figure in 0.05.
04:27.000 --> 04:32.400
So 1.05 rounded to 1 significant figure is simply 1.
04:32.440 --> 04:42.840
5,400 divided by 107 is equal to 50.4672 and the number continues on infinitely.
04:42.840 --> 04:50.400
5,400 has 2 significant figures, the 0's at the end do not count as significant figures.
04:50.400 --> 04:59.520
While 107 has 3 significant figures, remember that 0's sandwiched between non-zero numbers count as significant figures.
04:59.520 --> 05:06.920
This means that we have to round our answer to 2 significant figures, and this will give us simply 50.
05:06.920 --> 05:13.640
To show that the 0 in the 50 is significant, we will put a decimal point after the 0.
05:13.640 --> 05:20.480
Using the decimal point this way is somewhat unusual, and you will rarely come across this situation.
05:20.480 --> 05:23.480
Let's finish with powers and routes.
05:23.480 --> 05:31.720
15 to the power of 3 is 3,375 and 15 has 2 significant figures.
05:31.720 --> 05:42.600
This is what we will round to, so we get 3,481 under the 4th route is 3, and 81 has 2 significant figures.
05:42.600 --> 05:49.240
Not 3 is already to 1 significant figure, but we still have to try to give it to 2 significant figures,
05:49.240 --> 05:53.960
which will mean that we are going to write it as 3.0.
05:53.960 --> 05:58.920
Again, this is a relatively rare case that you will not see to often.
05:58.920 --> 06:01.960
Let's summarize what we have learned about estimation.
06:01.960 --> 06:07.840
When we measure something using measuring equipment, we never get an exactly accurate result,
06:07.840 --> 06:12.200
so we need to use estimation when reporting the measured value.
06:12.200 --> 06:15.000
In physics, we often encounter graphs.
06:15.080 --> 06:21.880
In our working with graphs, we often have to estimate a certain property or value on this graph.
06:21.880 --> 06:26.120
In our example, we estimated the area under a graph.
06:26.120 --> 06:29.080
Rounding is a type of estimation.
06:29.080 --> 06:33.000
We discussed how to round after carrying out a calculation.
06:33.000 --> 06:39.480
So when we round after an addition or subtraction, we have to round to the same decimal place
06:39.480 --> 06:42.040
as in the least accurate number.
06:42.040 --> 06:47.560
After a multiplication or division, we round to the same number of significant figures
06:47.560 --> 06:51.320
as the number of significant figures in the least accurate number.
06:52.200 --> 06:56.280
And finally, when we raise a number to a power or take its root,
06:56.840 --> 07:01.400
we round to the same number of significant figures as in this original number.
07:02.120 --> 07:08.120
This wraps up our discussion of estimation, which is the final video in sub-topic 1.1.
07:08.120 --> 07:15.480
In the first video of sub-topic 1.2, we will discuss random and systematic errors.