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class="fa fa-fw"></i><a href="../886/hybridization.html">Hybridization</a></label></li></ul></div> <button id="show-periodic-table" class="btn btn-default btn-block" style="margin-bottom: 10px"><i class="fa fa-table"></i>&nbsp;&nbsp;Periodic table</button> <div class="hidden-xs hidden-sm"> <button class="btn btn-default btn-block text-xs-center" data-toggle="modal" data-target="#modal-feedback" style="margin-bottom: 10px"><i class="fa fa-send"></i>&nbsp;&nbsp;Feedback</button> </div> </div> <div class="col-md-9" id="main-column"> <h1 class="page_title"> Covalent structure <a href="#" class="mark-page-favorite pull-right" data-pid="882" title="Mark as favorite" onclick="return false;"><i class="fa fa-star-o"></i></a> </h1> <ol class="breadcrumb"> <li><a href="../../../chemistry.html"><i class="fa fa-home"></i></a><i class="fa fa-fw fa-chevron-right divider"></i></li><li><a href="../357/bonding-and-structure.html">Bonding and Structure</a><i class="fa fa-fw fa-chevron-right divider"></i></li><li><span class="gray">Covalent structure</span></li> <span class="pull-right" style="color: #555" title="Suggested study time: 60 minutes"><i class="fa fa-clock-o"></i> 60&apos;</span> </ol> <article id="main-article"> <p>&nbsp;<img alt="" src="../../images/test-images/screenshot-2020-07-23-at-15.01.32-1.png" style="width: 160px; height: 150px; float: left;">Our model of covalent bonding and structure is based on the Bohr model of the atom and represented with Lewis diagrams. Lewis diagrams can be drawn with dots and crosses or with lines that represent a pair of outer-shell (valence) electrons.. It is important to become familiar with both notations; dots and/or crosses, or lines, so these notations are used interchangeably throughout this website. Always check that you have the correct number of electrons in total after you&#39;ve drawn a covalent molecule; it is easy to slip up here!</p> <hr class="hidden-separator"> <div class="panel panel-has-colored-body panel-turquoise"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Key concepts</p> </div> </div> <div class="panel-body"> <div> <div class="panel-body"> <div> <p>Ensure you are confident using the terms below and learn the asterisked* definitions</p> <p><strong>a polar bond*</strong>, <strong>a dative (coordinate) bond*</strong>, <strong>VSEPR theory*</strong>, a polar molecule, the octet rule, expanded octet, incomplete octet, valency, resonance structures, delocalised electrons, allotropes, lattice (or giant) structure.</p> <div class="tib-flashcard"><a class="show-flashcards btn btn-success btn-xs-block btn-block " data-levels="1" data-mode="Normal" data-topics="606" data-subject-id="7" data-n-flashcards="12" style="text-align:center">Show flashcards</a></div><hr> &nbsp; <div class="panel panel-has-colored-body panel-has-border panel-turquoise"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Understanding Resonance</p> </div> </div> <div class="panel-body"> <div>Understanding that resonance is an adjustment to our Lewis (dot-cross) diagram model of bonding.</div> <div class="video-embed vimeo"><iframe allow="accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture" allowfullscreen="" mozallowfullscreen="" webkitallowfullscreen="" height="420" width="100%" src="https://player.vimeo.com/video/407161843"></iframe></div> </div> <div class="panel-footer"> <div>&nbsp;</div> </div> </div> </div> </div> </div> </div> </div> <div class="panel panel-yellow panel-has-colored-body"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Essentials</p> </div> </div> <div class="panel-body"> <div> <p>&nbsp;&nbsp;&nbsp; The revision cards contain all of the essential content:</p> <div id="carousel-181" class="dynamic-gallery carousel slide" data-id="181"><div class="carousel-inner" role="listbox"><div class="item active"><a class="fancy" href="../../../std-galleries/7-181/screenshot-2020-04-14-at-124904.png" data-fancybox="gallery-181" title="" data-caption=""><img alt="" src="../../../std-galleries/7-181/screenshot-2020-04-14-at-124904.png"></a></div><div class="item "><a class="fancy" href="../../../std-galleries/7-181/screenshot-2020-04-14-at-124922.png" data-fancybox="gallery-181" title="" data-caption=""><img alt="" src="../../../std-galleries/7-181/screenshot-2020-04-14-at-124922.png"></a></div><div class="item "><a class="fancy" href="../../../std-galleries/7-181/screenshot-2020-07-30-at-104839.png" data-fancybox="gallery-181" title="" data-caption=""><img alt="" src="../../../std-galleries/7-181/screenshot-2020-07-30-at-104839.png"></a></div><div 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</div> <div class="panel-body"> <div> <div class="panel-body"> <div> <div class="tib-quiz" data-stats="7-136-882"><div class="label label-default q-number">1</div><div class="exercise shadow-bottom"><div class="q-question"><p>Which of the following are included in the rules of VSEPR (Valence Shell Electron Pair Repulsion) theory?</p><p><strong>1: </strong> The repulsion exhibited by a lone pair of electrons on a bonding pair is <strong>greater</strong> <strong>than</strong> the repulsion exhibited by a bonding pair on another bonding pair.</p><p><strong>2:</strong> Electron domains will repel as far apart as possible (in 3D space) around a central atom.</p><p><strong>3:</strong> The repulsion exhibited by a lone pair of electrons on another lone pair is<strong> less than </strong>the repulsion exhibited by a bonding pair on another bonding pair.</p></div><div class="q-answer"><p><label class="radio"> <input class="c" type="radio"> <span>1 and 2 only</span></label> </p><p><label class="radio"> <input type="radio"> <span>2 only</span></label> </p><p><label class="radio"> <input type="radio"> <span>2 and 3 only</span></label> </p><p><label class="radio"> <input type="radio"> <span>1, 2 and 3</span></label> </p></div><div class="q-explanation">1 and 2 are included in the VSEPR rules. 3 is incorrect as it is written; to be correct the words in bold would need to read <strong>&#39;greater than&#39;</strong>. Remember: Lone pair-lone pair repulsion &gt; lone pair- bonding pair repulsion &gt; bonding pair-bonding pair repulsion. The lone pairs are more &#39;diffuse&#39; and &#39;take up more space&#39; around the central atom.</div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">2</div><div class="exercise shadow-bottom"><div class="q-question"><p>Draw a Lewis (dot-cross) diagram for silane (SiH<sub>4</sub>). What is the shape around the central silicon atom and what are the likely bond angles?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>Tetrahedral; 90&deg;</span></label> </p><p><label class="radio"> <input type="radio"> <span>Trigonal pyramidal; 107&deg;</span></label> </p><p><label class="radio"> <input type="radio"> <span>Square planar; 90&deg;</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>Tetrahedral; 109.5&deg;</span></label> </p></div><div class="q-explanation"><p>Silane is the same shape as methane (CH<sub>4</sub>); <strong>tetrahedral</strong>, with bond angles of <strong>109.5&deg;</strong>. The Lewis diagram and shape are drawn below. Remember that molecules are three-dimensional, even though we draw the Lewis diagrams in two dimensions on the page.</p><p><img alt="" height="251" src="../../images/chemical-bonding-and-structure/silane.png" width="570"></p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">3</div><div class="exercise shadow-bottom"><div class="q-question"><p>Draw a Lewis (dot-cross) diagram for phosphine (PH<sub>3</sub>). What is the shape around the central phosphorus atom and what are the likely bond angles?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>Trigonal planar; 120&deg;</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>Trigonal pyramidal; 107&deg;</span></label> </p><p><label class="radio"> <input type="radio"> <span>Trigonal planar; 90&deg;</span></label> </p><p><label class="radio"> <input type="radio"> <span>Tetrahedral; 109.5&deg;</span></label> </p></div><div class="q-explanation"><p>Phosphine is the same shape as ammonia (NH<sub>3</sub>); <strong>trigonal pyramidal</strong>, with bond angles that might be estimated at approx <strong>107&deg;</strong> (although they are lower). The <strong>electron domains </strong>form a tetrahedral shape, but one bond is missing (it is a lone pair).</p><p>The Lewis diagram and shape are drawn below. Remember that molecules are three-dimensional, even though we draw the Lewis diagrams in two dimensions on the page.</p><p><img alt="" height="252" src="../../images/chemical-bonding-and-structure/phosphine.png" width="642"></p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">4</div><div class="exercise shadow-bottom"><div class="q-question"><p>Draw a Lewis (dot-cross) diagram for hydrogen sulfide (H<sub>2</sub>S). What is the shape around the central sulfur atom and what are the likely bond angles?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>Linear; 180&deg;</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>Bent; 104.5&deg;</span></label> </p><p><label class="radio"> <input type="radio"> <span>Tetrahedral; 109.5&deg;</span></label> </p><p><label class="radio"> <input type="radio"> <span>Linear; 90&deg;</span></label> </p></div><div class="q-explanation"><p>Hydrogen sulfide is the same shape as water (H<sub>2</sub>O); <strong>bent</strong>, with bond angles that might be estimated as approx <strong>104.5&deg;</strong> (although they are lower). The<strong> electron domains </strong>form a tetrahedral shape, but two bonds are missing (they are lone pairs).</p><p>The Lewis diagram and shape are drawn below. Remember that molecules are three-dimensional, even though we draw the Lewis diagrams in two dimensions on the page.</p><p><img alt="" height="244" src="../../images/chemical-bonding-and-structure/hydrogen-sulfide.png" width="644"></p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">5</div><div class="exercise shadow-bottom"><div class="q-question"><p>How many electrons in total in the valence (outer) electron shells of boron and beryllium respectively in BCl<sub>3</sub> and BeCl<sub>2</sub>?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>Boron 8; beryllium 8</span></label> </p><p><label class="radio"> <input type="radio"> <span>Boron 2; beryllium 3</span></label> </p><p><label class="radio"> <input type="radio"> <span>Boron 6; beryllium 8</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>Boron 6; beryllium 4</span></label> </p></div><div class="q-explanation"><p>Boron and beryllium can form stable molecules with incomplete valence shells. Boron in BCl<sub>3</sub> forms only three single bonds with each chlorine; a total of 6 electrons in the valence shell. Beryllium in BeCl<sub>2</sub> forms only two single bonds with each chlorine; a total of 4 electrons in the valence shell.</p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">6</div><div class="exercise shadow-bottom"><div class="q-question"><p>What are the shapes and bond angles around the central boron and beryllium atoms in BCl<sub>3</sub> and BeCl<sub>2</sub> respectively?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>Trigonal pyramidal, 107&deg;; bent, 104.5&deg;</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>Trigonal planar, 120&deg;; linear, 180&deg;</span></label> </p><p><label class="radio"> <input type="radio"> <span>Trigonal pyramidal, 107&deg;; linear, 180&deg;</span></label> </p><p><label class="radio"> <input type="radio"> <span>Trigonal planar, 120&deg;; bent, 104.5&deg;</span></label> </p></div><div class="q-explanation"><p>Boron and beryllium can form stable molecules with incomplete valence shells. Boron in BCl<sub>3</sub> forms only three single bonds with each chlorine; a total of 6 electrons in the valence shell. Beryllium in BeCl<sub>2</sub> forms only two single bonds with each chlorine; a total of 4 electrons in the valence shell.</p><p>Thus in BCl<sub>3</sub> and BeCl<sub>2</sub> respectively the shapes and bond angles are trigonal planar, 120&deg; and linear, 180&deg;.</p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">7</div><div class="exercise shadow-bottom"><div class="q-question"><p>Look at the table below:</p><table border="0" cellpadding="0" cellspacing="0" style="width: 100%;"><tbody><tr><td style="text-align: center;"><p>Chemical</p></td><td style="text-align: center;">Melting/boiling point</td><td style="text-align: center;"><p>Electrical conductivity</p><p>(solid)</p></td><td style="text-align: center;"><p>Electrical conductivity</p><p>(molten)</p></td></tr><tr><td style="text-align: center;">W</td><td style="text-align: center;">high</td><td style="text-align: center;">high</td><td style="text-align: center;">high</td></tr><tr><td style="text-align: center;">X</td><td style="text-align: center;">high</td><td style="text-align: center;">nil</td><td style="text-align: center;">high</td></tr><tr><td style="text-align: center;">Y</td><td style="text-align: center;">high</td><td style="text-align: center;">nil</td><td style="text-align: center;">nil</td></tr><tr><td style="text-align: center;">Z</td><td style="text-align: center;">low</td><td style="text-align: center;">nil</td><td style="text-align: center;">nil</td></tr></tbody></table><p>Which of the four chemicals is likely to be a chemical with a giant covalent structure, like silicon dioxide?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>Z</span></label> </p><p><label class="radio"> <input type="radio"> <span>X</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>Y</span></label> </p><p><label class="radio"> <input type="radio"> <span>W</span></label> </p></div><div class="q-explanation"><p>Giant covalent structures are likely to have high melting and boiling points; it takes a lot of energy to break the network of strong covalent bonds. They are also unlikely to conduct electricity in any state (graphite is an exception) as they do not usually have mobile electrons or mobile ions to carry charge.</p><p>So Y is the correct answer.</p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">8</div><div class="exercise shadow-bottom"><div class="q-question"><p>Look at the table below:</p><table border="0" cellpadding="0" cellspacing="0" style="width: 100%;"><tbody><tr><td style="text-align: center;"><p>Chemical</p></td><td style="text-align: center;">Melting/boiling point</td><td style="text-align: center;"><p>Electrical conductivity</p><p>(solid)</p></td><td style="text-align: center;"><p>Electrical conductivity</p><p>(molten)</p></td></tr><tr><td style="text-align: center;">W</td><td style="text-align: center;">high</td><td style="text-align: center;">high</td><td style="text-align: center;">high</td></tr><tr><td style="text-align: center;">X</td><td style="text-align: center;">high</td><td style="text-align: center;">nil</td><td style="text-align: center;">high</td></tr><tr><td style="text-align: center;">Y</td><td style="text-align: center;">high</td><td style="text-align: center;">nil</td><td style="text-align: center;">nil</td></tr><tr><td style="text-align: center;">Z</td><td style="text-align: center;">low</td><td style="text-align: center;">nil</td><td style="text-align: center;">nil</td></tr></tbody></table><p>Which of the four chemicals is likely to be a chemical with a simple (molecular) covalent structure?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>W</span></label> </p><p><label class="radio"> <input type="radio"> <span>X</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>Z</span></label> </p><p><label class="radio"> <input type="radio"> <span>Y</span></label> </p></div><div class="q-explanation"><p>Simple covalent structures are likely to have low melting and boiling points; it does not take much energy to break the relatively weak intermolecular forces between molecules. They are also unlikely to conduct electricity in any state as they do not usually have mobile electrons or mobile ions to carry charge.</p><p>So Z is the correct answer.</p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">9</div><div class="exercise shadow-bottom"><div class="q-question"><p>Allotropes of carbon include diamond, graphite and buckminsterfullerene (C<sub>60</sub>). How many bonds does each carbon form connecting to another carbon atom in each of these allotropes respectively?</p></div><div class="q-answer"><p><label class="radio"> <input class="c" type="radio"> <span>Diamond, 4 : Graphite, 3 : Buckminsterfullerene, 3</span></label> </p><p><label class="radio"> <input type="radio"> <span>Diamond, 3 : Graphite, 3 : Buckminsterfullerene, 3</span></label> </p><p><label class="radio"> <input type="radio"> <span>Diamond, 4 : Graphite, 3 : Buckminsterfullerene, 4</span></label> </p><p><label class="radio"> <input type="radio"> <span>Diamond, 4 : Graphite, 4 : Buckminsterfullerene, 4</span></label> </p></div><div class="q-explanation"><p>In <strong>diamond </strong>the carbon atoms are bonded in a tetrahedral arrangement to <strong>4 </strong>other carbon atoms, in a giant covalent structure.</p><p>In <strong>graphite </strong>the carbon atoms are bonded in a trigonal planar arrangement to <strong>3 </strong>other carbon atoms, in a giant covalent structure, with carbon hexagon rings, in layers. (The fourth electron from every carbon atom is delocalised between the layers and holds the layers together.)</p><p>In <strong>buckminsterfullerene </strong>the carbon atoms are bonded in a trigonal planar arrangement to <strong>3 </strong>other carbon atoms, forming the surface of the C<sub>60</sub> &#39;carbon football&#39; molecule with interlinking carbon hexagons (20) and pentagons (12).</p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">10</div><div class="exercise shadow-bottom"><div class="q-question"><p>Which is the best description of why graphite in the solid state can conduct electricity and why graphite is a good solid state lubricant respectively?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>The delocalised electrons are free to move between layers: The atoms in the lattice and free to move.</span></label> </p><p><label class="radio"> <input type="radio"> <span>The ions are free to move between layers: The layers of atoms in the lattice can slide over one-another.</span></label> </p><p><label class="radio"> <input type="radio"> <span>The ions are free to move between layers: The atoms in the lattice are free to move. </span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>The delocalised electrons are free to move between layers: The layers of atoms in the lattice can slide over one-another.</span></label> </p></div><div class="q-explanation"><p>In graphite the carbon atoms are bonded in a trigonal planar arrangement to 3<strong> </strong>other carbon atoms, in a giant covalent structure, with carbon hexagon rings, in layers. The fourth electron from every carbon atom is delocalised between the layers and holds the layers together (weakly).</p><p>Graphite conducts electricity in the solid state because the delocalised electrons between layers are able to move and carry charge.</p><p>Graphite is a good solid state lubricant because the layers of atoms are able to slide over one-another; the London dispersion forces between the layers are weak and easily broken. Individual atoms cannot move independently, but the layers can easily slide off the structure (think of a pencil marking a piece of paper).</p><p>The correct answer is therefore: &#39;The delocalised electrons are free to move between layers: The layers of atoms in the lattice can slide over one-another&#39;.</p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">11</div><div class="exercise shadow-bottom"><div class="q-question"><p>Which of the following molecules is likely to be polar?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>C<sub>2</sub>H<sub>6</sub></span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>CH<sub>3</sub>Cl</span></label> </p><p><label class="radio"> <input type="radio"> <span>CCl<sub>4</sub></span></label> </p><p><label class="radio"> <input type="radio"> <span>CH<sub>4</sub></span></label> </p></div><div class="q-explanation"><p>To be polar, a molecule must have polar bonds (differences in electronegativity) within it and must have asymmetric geometry (molecules will then have an overall dipole moment). If the dipoles of polar bonds cancel out because the molecule is symmetrical, then the molecule will have no overall dipole.</p><p>The C&ndash;H bonds are not considered to be significantly polar, and in addition, CH<sub>4</sub> and C<sub>2</sub>H<sub>6</sub> both have symmetrical geometry.</p><p>The C<sup>&delta;+</sup>&ndash;Cl<sup>&delta;&ndash;</sup> bond is polar. In CCl<sub>4</sub> the dipoles cancel as the molecule is symmetrical, but in CH<sub>3</sub>Cl the dipoles will not cancel out and CH<sub>3</sub>Cl is therefore polar.</p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">12</div><div class="exercise shadow-bottom"><div class="q-question"><p>When the bonding in a chemical species cannot be adequately represented by one single Lewis diagram, resonance structures may be used. Which of the following chemical species exhibit resonance?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>C<sub>2</sub>H<sub>6</sub></span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>CO<sub>3</sub><sup>2&ndash;</sup></span></label> </p><p><label class="radio"> <input type="radio"> <span>OH<sup>&ndash;</sup></span></label> </p><p><label class="radio"> <input type="radio"> <span>CO<sub>2</sub></span></label> </p></div><div class="q-explanation"><p>Lewis (dot-cross) diagrams for C<sub>2</sub>H<sub>6</sub>, OH<sup>&ndash;</sup> and CO<sub>2</sub> may all be drawn that accurately represent these species in terms of bond length and shape etc. The carbonate ion CO<sub>3</sub><sup>2&ndash;</sup> is said to exhibit resonance, because the shape of the compound ion with three C&ndash;O bonds of<strong> equal length </strong>cannot be represented by a conventional Lewis diagram. The resonance structures are shown below (showing bonds only for clarity; lone pairs are not shown):</p><p><img alt="" height="191" src="../../images/chemical-bonding-and-structure/carbonate.png" width="667"></p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="label label-default q-number">13</div><div class="exercise shadow-bottom"><div class="q-question"><p>When the bonding in a chemical species cannot be adequately represented by one single Lewis diagram, resonance structures may be used. When the resonance structures for a molecule of ozone, O<sub>3</sub>, are drawn, how many bonds do each of the three oxygen atoms form?</p></div><div class="q-answer"><p><label class="radio"> <input type="radio"> <span>2: 3: 2</span></label> </p><p><label class="radio"> <input type="radio"> <span>2: 2: 2</span></label> </p><p><label class="radio"> <input type="radio"> <span>3: 1: 3</span></label> </p><p><label class="radio"> <input class="c" type="radio"> <span>2: 3: 1</span></label> </p></div><div class="q-explanation"><p>The ozone molecule is said to exhibit resonance, because the shape of the molecule with two O&ndash;O bonds of<strong> equal length </strong>cannot be represented by a conventional Lewis diagram. The resonance structures are shown below (showing bonds only for clarity; lone pairs are not shown). The oxygen atoms form 2: 3: 1 bonds (or vica versa) respectively. The arrow represents a coordinate (dative) bond.</p><p><img alt="" height="184" src="../../images/chemical-bonding-and-structure/ozone.png" width="594"></p></div><div class="actions"><span class="score" data-score="0"></span><button class="btn btn-default btn-sm btn-xs-block text-xs-center check"><i class="fa fa-check-square-o"></i> Check</button></div></div><div class="totals"><span class="score"></span><button class="btn btn-success btn-block text-center check-total"><i class="fa fa-check-square-o"></i> Check</button></div></div><hr> </div> </div> </div> </div> <div class="panel-footer"> <div>&nbsp;</div> </div> </div> <div class="panel panel-has-colored-body panel-default"> <div class="panel-heading"><a class="expander" href="#"><span class="fa fa-plus"></span></a> <div> <p>Exam-style questions</p> </div> </div> <div class="panel-body"> <h4>Paper 1</h4> <h5>Core (SL&amp;HL):&nbsp;&nbsp;&nbsp;&nbsp;<a href="../2161/bonding-and-structure-core-sl-and-hl-paper-1-questions.html" title="Bonding and Structure core (SL and HL) paper 1 questions">Bonding and Structure core (SL and HL) paper 1 questions</a></h5> <h5>AHL (HL only):&nbsp;&nbsp;&nbsp;&nbsp;<a href="../2703/bonding-and-structure-ahl-hl-only-paper-1-questions.html" title=" Bonding and Structure AHL (HL only) paper 1 questions">Bonding and Structure AHL (HL only) paper 1 questions</a></h5> <h4>Paper 2</h4> <h5>Core (SL&amp;HL):&nbsp;&nbsp;&nbsp;<a href="../2704/bonding-structure-core-sl-hl-paper-2-questions.html" title="Bonding &amp; 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