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</div><h2>HL Paper 3</h2><div class="question">
<p>In an acidic soil, nitrate ions may undergo reduction to form ammonium ions. Deduce a half-equation for the reaction.</p>
</div>
<br><hr><br><div class="specification">
<p class="p1">Enzymes are catalysts that increase the rate of all biochemical reactions, including those involved in respiration.</p>
</div>

<div class="specification">
<p class="p1">Cytochrome oxidase is a complex enzyme that catalyses the reduction of oxygen in the final stage of aerobic respiration. This enzyme is inhibited both by nitrogen(II) oxide, NO, and separately by cyanide ions, \({\text{C}}{{\text{N}}^ - }\). It has been suggested that NO acts competitively while \({\text{C}}{{\text{N}}^ - }\) acts non-competitively in inhibiting the enzyme. Experiments were carried out to test this hypothesis.</p>
</div>

<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p class="p1">The graph below shows the effect of substrate concentration on the rate of the reaction in the absence of an inhibitor. Draw and label the results of the <strong>two</strong> experiments showing how the rate of the reaction changes in the presence of NO and in the presence of \({\text{C}}{{\text{N}}^ - }\), if the hypothesis is correct.</p>
<p class="p1" style="text-align: center;"><img src="images/Schermafbeelding_2016-08-25_om_16.22.59.png" alt="N13/4/CHEMI/HP3/ENG/TZ0/09.b.ii"></p>
<div class="marks">[2]</div>
<div class="question_part_label">b.ii.</div>
</div>
<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p class="p1">Suggest a reason why it is more likely that NO, rather than \({\text{C}}{{\text{N}}^ - }\), acts competitively.</p>
<div class="marks">[1]</div>
<div class="question_part_label">b.iii.</div>
</div>
<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p class="p1">The reducing agent in the cytochrome oxidase reaction is a species that can be denoted as \({\text{X}}{{\text{H}}_{\text{2}}}\) in the reduced form. Using this notation, deduce an equation for the reaction of \({\text{X}}{{\text{H}}_{\text{2}}}\) and \({{\text{O}}_{\text{2}}}\), and outline, using oxidation numbers, why it is a redox reaction.</p>
<div class="marks">[2]</div>
<div class="question_part_label">b.iv.</div>
</div>
<br><hr><br>