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</div><h2>SL Paper 3</h2><div class="specification">
<p class="p1">Alkenes can undergo electrophilic addition reactions with bromine and with hydrogen bromide.</p>
</div>
<div class="specification">
<p class="p1">Name the product formed when but-2-ene reacts with</p>
</div>
<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p class="p1">Explain how a bromine molecule is able to act as an electrophile.</p>
<div class="marks">[1]</div>
<div class="question_part_label">a.</div>
</div>
<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p class="p1">(i) bromine.</p>
<p class="p1">(ii) hydrogen bromide.</p>
<div class="marks">[2]</div>
<div class="question_part_label">b.</div>
</div>
<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p class="p1">When but-1-ene reacts with hydrogen bromide, two possible organic products could be formed but in practice only one organic product is obtained in high yield. Explain the mechanism for this reaction using curly arrows to represent the movement of electron pairs and explain clearly why only one organic product is formed.</p>
<div class="marks">[4]</div>
<div class="question_part_label">c.</div>
</div>
<br><hr><br><div class="question" style="padding-left: 20px; padding-right: 20px;">
<p class="p1">Deduce a two-step reaction pathway which can be used to convert 1-bromopropane into butanoic acid. Draw the structural formula of the organic product formed for each step and identify the reagents involved.</p>
<div class="marks">[4]</div>
<div class="question_part_label">a.</div>
</div>
<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p class="p1">Deduce a two-step reaction pathway which can be used to convert propan-2-ol into 1,2-dibromopropane. Draw the structural formula of the organic product formed for each step and identify the reagents involved.</p>
<div class="marks">[4]</div>
<div class="question_part_label">b.</div>
</div>
<br><hr><br><div class="specification">
<p class="p1">Addition of hydrogen halides to unsymmetrical alkenes produces a mixture of halogenoalkanes. The latter can be converted into Grignard reagents by reaction with magnesium metal and then used for the preparation of various organic molecules with an increased number of carbon atoms.</p>
</div>
<div class="question">
<p class="p1">Describe, using equations and curly arrows to represent the movement of electron pairs, the mechanism of the reaction between propene and hydrogen bromide. Compare the relative stabilities of the two intermediate carbocations which lead to the formation of the major and minor products.</p>
</div>
<br><hr><br><div class="specification">
<p class="p1">Draw the structural formula of the <strong>major </strong>organic products, <strong>A </strong>and <strong>B</strong>, formed in the following reactions.</p>
</div>
<div class="question">
<p class="p1">\({\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{CH=C}}{{\text{H}}_2} + {\text{HBr}} \to \) <strong>A</strong></p>
<p class="p1"><strong>A</strong>:</p>
</div>
<br><hr><br><div class="specification">
<p>The cumene process is used for the production of both propanone and phenol. The overall reaction is shown in the equation below.</p>
<p style="text-align: center;"><img src="images/Schermafbeelding_2016-08-23_om_17.08.44.png" alt="N14/4/CHEMI/SP3/ENG/TZ0/26"></p>
<p>This process is important in the polymer industry. Propanone can be converted into methyl methacrylate, the monomer used to make Perspex<sup>®</sup>, and phenol is used in phenol-methanal resins, which are important thermosetting plastics.</p>
</div>
<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p>State and explain how the presence of a halogen substituent might affect the acidity of carboxylic acids.</p>
<div class="marks">[3]</div>
<div class="question_part_label">a.ii.</div>
</div>
<div class="question" style="padding-left: 20px; padding-right: 20px;">
<p>Propanone could also be formed from propene by reaction with steam over an acidic catalyst, followed by oxidation of the product.</p>
<p>The reaction of propene with water can yield two possible products. Explain, in terms of the stability of the intermediate carbocations, why one is formed in much greater quantities than the other.</p>
<div class="marks">[3]</div>
<div class="question_part_label">d.</div>
</div>
<br><hr><br>