Date | May 2019 | Marks available | 2 | Reference code | 19M.2.SL.TZ2.S_4 |
Level | Standard Level | Paper | Paper 2 | Time zone | Time zone 2 |
Command term | Find | Question number | S_4 | Adapted from | N/A |
Question
OAB is a sector of the circle with centre O and radius r, as shown in the following diagram.
The angle AOB is θ radians, where 0<θ<π2.
The point C lies on OA and OA is perpendicular to BC.
Find the area of triangle OBC in terms of r and θ.
Markscheme
valid approach (M1)
eg 12OC×OBsinθ , BC=rsinθ, 12rcosθ×BC , 12rsinθ×OC
area =12r2sinθcosθ (=14r2sin(2θ)) (must be in terms of r and θ) A1 N2
[2 marks]
Examiners report
[N/A]