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Date November 2017 Marks available 3 Reference code 17N.1.AHL.TZ0.H_3
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 0
Command term Hence or otherwise Question number H_3 Adapted from N/A

Question

Consider the polynomial q(x)=3x311x2+kx+8.

Given that q(x) has a factor (x4), find the value of k.

[3]
a.

Hence or otherwise, factorize q(x) as a product of linear factors.

[3]
b.

Markscheme

q(4)=0     (M1)

192176+4k+8=0 (24+4k=0)     A1

k=6     A1

[3 marks]

a.

3x311x26x+8=(x4)(3x2+px2)

equate coefficients of x2:     (M1)

12+p=11

p=1

(x4)(3x2+x2)     (A1)

(x4)(3x2)(x+1)     A1

 

Note:     Allow part (b) marks if any of this work is seen in part (a).

 

Note:     Allow equivalent methods (eg, synthetic division) for the M marks in each part.

 

[3 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 2—Functions » AHL 2.12—Factor and remainder theorems, sum and product of roots
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Topic 2—Functions

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