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Date May 2019 Marks available 3 Reference code 19M.1.AHL.TZ1.H_8
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 1
Command term Sketch Question number H_8 Adapted from N/A

Question

The graph of y=f(x), 0 ≤ x ≤ 5 is shown in the following diagram. The curve intercepts the x-axis at (1, 0) and (4, 0) and has a local minimum at (3, −1).

The shaded area enclosed by the curve y=f(x), the x-axis and the y-axis is 0.5. Given that f(0)=3,

The area enclosed by the curve y=f(x) and the x-axis between x=1 and x=4 is 2.5 .

Write down the x-coordinate of the point of inflexion on the graph of y=f(x).

[1]
a.

find the value of f(1).

[3]
b.

find the value of f(4).

[2]
c.

Sketch the curve y=f(x), 0 ≤ x ≤ 5 indicating clearly the coordinates of the maximum and minimum points and any intercepts with the coordinate axes.

[3]
d.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

3     A1

[1 mark]

a.

attempt to use definite integral of f(x)        (M1)

10f(x)dx=0.5

f(1)f(0)=0.5        (A1)

f(1)=0.5+3

= 3.5      A1

[3 marks]

b.

41f(x)dx=2.5       (A1)

Note: (A1) is for −2.5.

f(4)f(1)=2.5

f(4)=3.52.5

= 1      A1

[2 marks]

c.

    A1A1A1

A1 for correct shape over approximately the correct domain
A1 for maximum and minimum (coordinates or horizontal lines from 3.5 and 1 are required),
A1 for y-intercept at 3

[3 marks]

d.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.
[N/A]
d.

Syllabus sections

Topic 5 —Calculus » SL 5.5—Integration introduction, areas between curve and x axis
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